A force of 750 N is applied to a block of mass 102 kg to prevent it from sliding on a plane with an inclination angle 30° with the horizontal. If the coefficients of static friction and kinetic friction between the block and the plane are 0.4 and 0.3 respectively, then the frictional force acting on the block is
Text Solution
Verified by ExpertsD
Net force along the plane
= $P - mg \sin \theta$ = 750 - 500 = 250 N
Limiting friction = $F_{l} = \mu_{s} R = \mu_{s} mg \cos \theta$
= 0.4 × 102 × 9.8 × cos 30 = 346 N
As net external force is less than limiting friction therefore friction on the body will be 250 N.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems